A wire of length 2 units is cut into two parts which are bent respectively to form a square of side = x units and a circle of radius = r units. If the sum of the areas of the square and the circle so formed is minimum, then :
Length of wire = 2
Given 4x+2πr=2⇒2x+πr=1 ......(i)A=x2+πr2=(1−π2)2+πr2⇒dAdr=2(1−πr2)(−π2)+2πrFor max and min⇒dAdr=0π(1−πr)=4πr1=4r+πr ........(ii)From (i) and (ii)2x+πr=4r+πrx=2r