A wire of length 5 m is stretched by 1 mm by a force of 1 N. What is the value of energy stored in the wire?

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Solution

Energy stored = $= \frac{1}{2} \times F o r c e \times E x t e n s i o n$
$= \frac{1}{2} \times 1 \times 0.001 = 0.005 J o r 0.5 m J$ .

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A wire of length 5 m is stretched by 1 mm by a force of 1 N. What is the value of energy stored in the wire?

Energy stored = =12×Force×Extension=12×1×0.001=0.005Jor0.5mJ.

Energy stored = $= \frac{1}{2} \times F o r c e \times E x t e n s i o n$
$= \frac{1}{2} \times 1 \times 0.001 = 0.005 J o r 0.5 m J$ .