Question

A wire of length $86cm$ in bent in the form of a rectangle such that its length is $7cm$ more than its breadth. Find the length and the breadth of the rectangle so formed.

Answer 1

Let the length of rectangle be $l$

$\therefore$ breadth, $b=l-7$

Wire is bent in the form of rectangle, so the perimeter of rectangle will be equal to the length of the wire.

Perimeter of rectangle $=$ Length of wire $=2(l+b)$

$2(l+b)=86$

$\Rightarrow 2(l+l-7)=86\left[\text{on substituting the value of b}\right]$

$\Rightarrow 2l-7=43$

$\Rightarrow 2l=50$

$\therefore l=25cm$

So, length $=25cm$ and, Breadth, $b=l-7=25-7=18cm$