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Question

A wire of length 'I' is bent in the form of a circular ring, moment of inertia about its axis is

A
(I8π2)MI2
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B
(8π2)MI2
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C
(I4π2)MI2
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D
(4π2)MI2
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Solution

The correct option is C (I4π2)MI2
Lets consider M= mass of ring
I= length of circular ring
r= radius of circular ring
Length of wire is equal to the circumference of circular ring,
I=2πr
r=I2π. . . .(1)
The moment of inertia about the axis of circular ring is given by
Mr2=MI24π2=(14π2)MI2
The correct option C.


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