A wire of resistance 100 Ω is doubled on itself. The new resistance is
Let, the resistance of the resistor is R, length of resistor is L and cross-sectional area is A.
We know, R∝L and R∝1A
Also, when the length of resistor is doubled its cross-section area is halved therefore due to combined effect of these two R will decrease.
Hence, the new resistance say Rn is
Rn=(4)R
Rn=(4)×100
Rn=400Ω