a wire of resistance 18 ohm is bent to form an equilateral triangle. The resistance across any two vertices of the triangle is(in ohm)

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Solution

Consider the wire has uniform radius.

That would make each arm of the equilateral triangle have 18/3 = 6 ohm resistance.

Now between two vertices, there is a single 6
resistor in parallel with a series connection of two 6 ohm
resistor.

Therefore 12
Ω in parallel with 6ohm w
hich is equal
=12*6/(12+6)=72/18 =4 ohm

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