Question

A wire of resistance 20 ohm is bent in form of a circle. Find the equivalent resistance between two diametrically opposite ends.

• A. 40 ohm
• B. 20 ohm
• C. 10 ohm
• D. 5 ohm

Answer 1

The correct option is D

5 ohm

The upper semicircle will be 10 ohm and the bottom will be 10 ohm Now these two are in parallel to each other So the net we get as$\frac{1}{R}$ (net) = $\frac{1}{10}$ + $\frac{1}{10}$

R (net) = 5 ohm