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Question
A wire of resistance 3ohmand length 10cm is stretched to length 30cm.Assuming uniform cross section,new resistance?
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Solution
Original resistance = Ro = rho *l/A
The resistance of the conductor is directly proportional to its length and inversely proportional to its cross sectional area.
The wire is tripled of its previous length so the resistance will be 3l
and the new cross sectional area will be A/3
Rn = 3 * rho * l/ A/3
= 9R ( R = rho*l/A)
= 9*3 =27 Ohm
The resistance of the conductor is directly proportional to its length and inversely proportional to its cross sectional area.
The wire is tripled of its previous length so the resistance will be 3l
and the new cross sectional area will be A/3
Rn = 3 * rho * l/ A/3
= 9R ( R = rho*l/A)
= 9*3 =27 Ohm
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