Question

A wire of resistance 8 $\Omega$ is bent into a circle. Find the resistance across the diameter.

Answer 1

Given a wire of resistance $8\Omega$ is bent into a circle

To find the resistance across the diameter

Solution:

From the figure shown above,

resistance of the wire of half length=$4\Omega$

So the resistance across the diameter, AB is,

$R_{AB}=\frac{4\times 4}{4+4}⟹R_{AB}=\frac{16}{8}⟹R_{AB}=2\Omega$

is the required resistance aross AB