A wire of resistance $9 Ω$ is bent in a form of equilateral triangle. The equivalent resistance between any two of its vertices will be :

1 Ω

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2 Ω

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3 Ω

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9 Ω

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Solution

The correct option is B $2 Ω$

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A wire of resistance 9Ω is bent in a form of equilateral triangle. The equivalent resistance between any two of its vertices will be :

The correct option is B 2Ω

A wire of resistance $9 Ω$ is bent in a form of equilateral triangle. The equivalent resistance between any two of its vertices will be :

The correct option is B $2 Ω$