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Question

A wire potentiometer of length 11 m and resistance 1 Ω/m balances a standard cell voltage of 1.018 V at a length of 10 m 18 cm. If the voltage of the battery supplying the current through the potentiometer is 2.0 V, then the value of the series resistance connected to the potentiometer is

A
9 Ω
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B
90 Ω
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C
900 Ω
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D
990 Ω
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Solution

The correct option is A 9 Ω

Working current,

Iw=1.01810.18=0.1 A

Now, applying KVL,

2=(RS+11)0.1

Rs=9 Ω

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