A wire when bent in the form of a square encloses an area of $484 m^{2}$ . Find the largest area enclosed by the same wire when bent to form a rectangle of breadth $16$ m.

484 m^{2}

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448 m^{2}

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44 m^{2}

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48 m^{2}

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Solution

The correct option is A $448 m^{2}$
Area of square $= 484 m^{2}$
$= a^{2} = 484 m^{2}$
$a = 22 m$
Perimeter $= 4 a = 88 m$
Perimeter of square will be to equal to rectangle
$= 88 = 2 (l + 16)$
$44 = l + 16$
$l = 28$
Area $= l \times b$
$= 28 \times 16 = 448 m^{2}$

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A wire when bent in the form of a square encloses an area of 484m2. Find the largest area enclosed by the same wire when bent to form a rectangle of breadth 16 m.

The correct option is A 448m2Area of square =484 m2=a2=484 m2a=22 mPerimeter =4a=88 mPerimeter of square will be to equal to rectangle=88=2(l+16)44=l+16l=28Area =l×b=28×16=448 m2

A wire when bent in the form of a square encloses an area of $484 m^{2}$ . Find the largest area enclosed by the same wire when bent to form a rectangle of breadth $16$ m.

The correct option is A $448 m^{2}$
Area of square $= 484 m^{2}$
$= a^{2} = 484 m^{2}$
$a = 22 m$
Perimeter $= 4 a = 88 m$
Perimeter of square will be to equal to rectangle
$= 88 = 2 (l + 16)$
$44 = l + 16$
$l = 28$
Area $= l \times b$
$= 28 \times 16 = 448 m^{2}$