A wire, which passes through the hole in a small bead, is bent in the form of quarter of a circle. The wire is fixed vertically on ground as shown in the figure. The bead is released from near the top of the wire and it slides along the wire without friction. As the bead moves from $A$ to $B,$ the force it applies on the wire is

Always radially outwards

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Always radially inwards

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Radially inwards initially and radially outwards later

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Radially outwards initially and radially inwards later

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Solution

The correct option is C Radially inwards initially and radially outwards later
Answer (D)

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Q. A wire, which passes through a hole in a small bead, is bent in the form of a quarter of a circle. The wire is led vertically on ground as shown in the figure. The bead is released from near the top of the wire and it slides along the wire without friction. As the bead moves from A to B, the force it applies on the wire is:

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