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Standard X

Physics

Relation Between MA and VR

A woman draws...

Question

A woman draws water from a well using a fixed pulley. The mass of bucket and water together is $6 k g$ . The force applied by the woman is $70 N$ . What is the mechanical advantage ? (Take $g = 10 m s^{- 2}$ )

0.857

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0.657

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0.815

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Solution

The correct option is A $0.857$
Mechanical Advantage(M.A) of a pulley $= \frac{L o a d}{E f f o r t}$
Load $=$ mass of bucket $+$ water $= 6 k g - w t = 6 \times 10 N = 60 N$
Effort $= 70 N$
$M . A = \frac{60}{70} = 0.857$

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A woman draws water from a well using a fixed pulley. The mass of bucket and water together is 6kg. The force applied by the woman is 70N. What is the mechanical advantage ? (Take g=10ms−2)

The correct option is A 0.857Mechanical Advantage(M.A) of a pulley =LoadEffortLoad = mass of bucket + water =6 kg−wt=6×10 N=60 NEffort =70NM.A=6070=0.857

A woman draws water from a well using a fixed pulley. The mass of bucket and water together is $6 k g$ . The force applied by the woman is $70 N$ . What is the mechanical advantage ? (Take $g = 10 m s^{- 2}$ )

The correct option is A $0.857$
Mechanical Advantage(M.A) of a pulley $= \frac{L o a d}{E f f o r t}$
Load $=$ mass of bucket $+$ water $= 6 k g - w t = 6 \times 10 N = 60 N$
Effort $= 70 N$
$M . A = \frac{60}{70} = 0.857$