A woman draws water from a well using a fixed pulley. The mass of bucket and water together is 6 Kg. The force applied by the woman is 70 N. calculate the mechanical advantage. $[T a k e g = 10 m s^{2}]$

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Solution

The force applied by the women is $70 N$
The mass of bucket and water together is $= 6 k g$
Total load $= 6 \times 10 = 60 N$
Mechanical advantage M.A. $= \frac{L o a d}{E f f o r t} = \frac{60}{70} = 0.857$

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A woman draws water from a well using a fixed pulley. The mass of bucket and water together is 6 Kg. The force applied by the woman is 70 N. calculate the mechanical advantage. [Takeg=10ms2]

The force applied by the women is 70NThe mass of bucket and water together is =6kgTotal load =6×10=60NMechanical advantage M.A. =LoadEffort=6070=0.857

A woman draws water from a well using a fixed pulley. The mass of bucket and water together is 6 Kg. The force applied by the woman is 70 N. calculate the mechanical advantage. $[T a k e g = 10 m s^{2}]$

The force applied by the women is $70 N$
The mass of bucket and water together is $= 6 k g$
Total load $= 6 \times 10 = 60 N$
Mechanical advantage M.A. $= \frac{L o a d}{E f f o r t} = \frac{60}{70} = 0.857$