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Question
A woman has Rs 10,000 with her. She calculated that she could spend Rs x everyday on her holidays, She spends Rs(x-50) everyday and extended her holidays by 10 days.Calculate x.
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Solution
Let the no .of holidays be y
Spending x per day xy
Total money she has 10,000⟹xy=10,000
Similarly According to the question
(x−50)(y+10)=10,000xy+10x−50y−500=10,000x−5y−50=0x=5y+50y(5y+50)=10,000y2+10y=2000y2+50y−40y−2000=0(y−40)(y+50)=0y=40,−50⟹x=250
Let the no .of holidays be y
Spending x per day xy
Total money she has 10,000
⟹xy=10,000
(x−50)(y+10)=10,000xy+10x−50y−500=10,000x−5y−50=0x=5y+50y(5y+50)=10,000y2+10y=2000y2+50y−40y−2000=0(y−40)(y+50)=0y=40,−50⟹x=250
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