Question

A woman walks a certain distance in $84$ $min$, she then covers two thirds of it at $4$ $km/h$ and the rest at $5$ $km/h$ . Find the total distance she covered .

Answer 1

Given women walk a certain distance in $84$ minutes in the first two-thirds of the time she walked at $4kmph$

So distance covered in $1^{st}$ two-third is

$x=4kmph\times \frac{2}{3}\times 84min$

$=4\times \frac{2}{3}\times \frac{84}{60}hr$

$x=3.733km$

So remaining distance is

$y=5\times \frac{1}{3}\times \frac{84}{60}$

$=2.333km$

$\therefore$ Total distance $=x+y=6.067km$