A woman weight 400 N on earth. If she was on planet with twice the radius and twice the mass of the earth, how much would she weight?

400 N

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800 N

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200 N

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100 N

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1600 N

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Solution

The correct option is C 200 N
Here $m g = 400 N$
We know that earth's surface gravity is $g = \frac{G M}{R^{2}}$
For the planet, $g^{'} = \frac{G (2 M)}{(2 R)^{2}} = 0.5 \frac{G M}{R^{2}} = 0.5 g$
The the weight on the planet will be $m g^{'} = 0.5 m g = 0.5 \times 400 = 200 N$

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A woman weight 400 N on earth. If she was on planet with twice the radius and twice the mass of the earth, how much would she weight?

The correct option is C 200 NHere mg=400N We know that earth's surface gravity is g=GMR2For the planet, g′=G(2M)(2R)2=0.5GMR2=0.5gThe the weight on the planet will be mg′=0.5mg=0.5×400=200N

The correct option is C 200 N
Here $m g = 400 N$
We know that earth's surface gravity is $g = \frac{G M}{R^{2}}$
For the planet, $g^{'} = \frac{G (2 M)}{(2 R)^{2}} = 0.5 \frac{G M}{R^{2}} = 0.5 g$
The the weight on the planet will be $m g^{'} = 0.5 m g = 0.5 \times 400 = 200 N$