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Question

A woman with two genes, one for haemophilia and one for colour blindness on one of its X-chromosomes marries a normal man. The progeny will be

A
All sons haemophilic and colour blind
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B
50% haemophilic and colour blind sons and 50% normal sons
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C
All daughters haemophilic and colour blind
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D
50% haemophilic daughters and 50% colour blind daughters
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Solution

The correct option is B 50% haemophilic and colour blind sons and 50% normal sons
A woman with two genes, one for haemophilia and one for colour blindness on one of its X-chromosomes
marries a normal man. The progeny will be 50% haemophilic and colour blind sons and 50% normal sons.

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