From the laws of flotation
Weight of the wooden block=Weight of the glycerine displaced by immersed portion
(Vwood)(g)(RDwood)=(Vglycerine)(g)(RDglycerine)
(Vwood)(RDwood)=(Vglycerine)(RDglycerine)
RDglycerine=(Vwood)*(RDwood)/(Vglycerine) =(V)*(0.78)/(1−2/5)V =(V)*(0.78)/(3/5)V =1.3