A wooden block floats in water with two-third of its volume submerged. The density of wood is X $g m^{- 3}$ . When the same block is placed in oil, three-quarter of its volume is immersed in oil. Find $3 X$ in $g m^{- 3}$ .

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Solution

The correct option is B $2$
Let $X$ be the density of wood.

$\dfrac{Density of wood}{Density of water} = Part of block submerged

$\frac{X}{1} = \frac{2}{3}$

$∴ X = \frac{2}{3}$

$3 X = 2 g m^{- 3}$

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A wooden block floats in water with two-third of its volume submerged. The density of wood is X gm−3 . When the same block is placed in oil, three-quarter of its volume is immersed in oil. Find 3X in gm−3.

The correct option is B 2Let X be the density of wood.$\dfrac{Density of wood}{Density of water} = Part of block submergedX1=23∴X=233X=2 gm−3

A wooden block floats in water with two-third of its volume submerged. The density of wood is X $g m^{- 3}$ . When the same block is placed in oil, three-quarter of its volume is immersed in oil. Find $3 X$ in $g m^{- 3}$ .

The correct option is B $2$
Let $X$ be the density of wood.

$\dfrac{Density of wood}{Density of water} = Part of block submerged

$\frac{X}{1} = \frac{2}{3}$

$∴ X = \frac{2}{3}$

$3 X = 2 g m^{- 3}$