A wooden block is placed on a table top. Name the forces acting on the block and draw neat and labelled diagrams to show the point of application and direction of these forces.

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Solution

Forces acting on the wooden block are weight $m g$ of the block in downward direction and Normal action force $N$ between the point of contact, between the table and the block in the upward direction.

Point of application of N: Point A
Point of application of weight: Point B (Centre of gravity of block)
At equilibrium, both forces would be equal i.e
$N = m g$

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