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Question

A wooden block of density 860 kg/m3 at 00C is floating on benzene liquid of density 900 kg/m3 at 00C . The temperature at which the block just submerge in benzene is [γwood=8×105/0c,γbenzene=12×104/0c]


A
240 c
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B
420 c
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C
160 c
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D
320 c
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Solution

The correct option is C 420 c
It would submerge when the density is same.
8601+γwoodT=9001+γbenzeneT
43+0.0516T=45+0.0036T
0.048T=2
T=420C

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