A wooden block of mass 10 g is dropped from the top of a cliff 100 m high. Simultaneously, a bullet of mass 10 g is fired from the foot of the cliffupward with a velocity of 100 ms−1. At what time will the bullet and the block meet ?
Height of the tower =s1+s2=100 m.
Where s1 and s2 are the displacements covered by wooden block and bullet respectively before the collision.
For the block :
For the bullet :
Since, s1+s2=100 m
⇒ 100t = 100
⇒ t = 1s.