CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

A wooden block of mass 10 g is dropped from the top of a cliff 100 m high. Simultaneously, a bullet of mass 10 g is fired from the foot of the cliffupward with a velocity of 100 ms1. At what time will the bullet and the block meet ?


A
4 s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3 s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2 s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1 s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 1 s

Height of the tower =s1+s2=100 m.
Where s1 and s2 are the displacements covered by wooden block and bullet respectively before the collision.
For the block :
s1=12gt2=12×9.8×t2=4.9t2
For the bullet :
s2=ut12gt2
=100t12×9.8×t2=100t4.9t2
Since, s1+s2=100 m
4.9t2+100t4.9t2=100
100t = 100
t = 1s.


flag
Suggest Corrections
thumbs-up
33
mid-banner-image
mid-banner-image
Join BYJU'S Learning Program
Select...
similar_icon
Related Videos
thumbnail
lock
Equations of Motion
PHYSICS
Watch in App
Join BYJU'S Learning Program
Select...