A wooden cabinet is moved across the floor with a constant velocity of 0.5 m/s using a horizontal force of 120 N. What is the frictional force exerted by the floor on the cabinet?
A
-12 N
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B
0 N
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C
60 N
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D
-120 N
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Solution
The correct option is D -120 N The cabinet is moving with a constant velocity, i.e., the acceleration is zero. Therefore, the net force acting on the cabinet is also zero. It implies that the magnitude of the opposing frictional force is equal to the force exerted on the cabinet, i.e., 120 N. Thus, the frictional force is -120 N.