CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

A wooden cube just floats inside water with a 400 gm mass placed on it. When the mass is removed, the cube floats with its top surface 4 cm above the water level. What is the side of the cube?

A
6 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
8 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
10 cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
12 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 10 cm
Let L and d be the side of the cube and density of the cube respectively.
Given, weight of block, W=400 gm
In first case,
weight of the cube+weight of mass = weight of water displaced
(L3×d×g) + W = L3×ρ×g
(L3×d×g) + 400g = L3×1×g
L3×d = L3400........(1)
Density of water,ρ=1g/cm3
In second case, (L4) part of cube remains in water
weight of the cube= weight of water displaced
(L3×d×g) = L2×(L4)×ρ×g
L3×d = L2×(L4).......(2)
From (1) and (2) equations,
L3400= L2×(L4)
400= 4L2
L=10 cm

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon