Question

A wooden cube of side $10cm$ has mass $700g$. The part of it remains above the water surface while floating vertically on water surface is $Xcm$. Find $X$.

• A. $3$
• B. $7$
• C. $0$
• D. Can not be detemined

Answer 1

Answer: (A)

$3$

We know that the volume of part submerged in a liquid is given by, $V=\frac{Densityofbody}{Densityofliquid}$
Density of cube $=\frac{Mass}{Volume}$$=\frac{700g}{{10}^3}=0.7g/c{m}^3$
So, density of water $=1g/c{m}^3$
So, part of cube submerged in water $=\frac{Densityofbody}{Densityofwater}=0.7/1=7/10$
$\therefore$ Part of cube above water $=1-7/10=3/10$
i.e. $3cm$ of cube is above water.