A wooden cube of side 10cm is found to float in water. On keeping a weight of 50gm over its top, it is just submerged in the water. The specific gravity of wood is:

0.8

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0.9

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0.85

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0.95

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Solution

The correct option is C 0.95
Total weight of the body is equal to the displaced liquid.
$ρ_{b} V_{b} + 50 = V_{b} ρ_{w a t e r}$
$ρ_{b} \times 1000 + 50 = 1000 \times 1$
$ρ_{b} = 950$
Thus we calculate $ρ$ as 0.95

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A wooden cube of side 10cm is found to float in water. On keeping a weight of 50gm over its top, it is just submerged in the water. The specific gravity of wood is:

The correct option is C 0.95Total weight of the body is equal to the displaced liquid.ρbVb+50=Vbρwaterρb×1000+50=1000×1ρb=950Thus we calculate ρ as 0.95

The correct option is C 0.95
Total weight of the body is equal to the displaced liquid.
$ρ_{b} V_{b} + 50 = V_{b} ρ_{w a t e r}$
$ρ_{b} \times 1000 + 50 = 1000 \times 1$
$ρ_{b} = 950$
Thus we calculate $ρ$ as 0.95