A wooden object floats in water kept in a beaker. The object is near a side of the beaker. Let PA, PB, PC be the pressures at the three points A, B and C of the bottom as shown in the figure.
PA = PB = PC
"If the pressure in a liquid is changed at a particular point, the change is transmitted to the entire liquid without getting diminished in magnitude”
At the same depth inside a liquid, pressure is same. A block floating will not change this affect
ThereforePA=PB=PC