Question

A wooden object floats in water kept in a beaker. The object is near a side of the beaker. Let $P_1,P_2,P_3$ be the pressures at the three $A,B$ and $C$ of the bottom as shown in the figure.

• A. $P_1=P_2=P_3$
• B. $P_1<P_2<P_3$
• C. $P_1>P_2>P_3$
• D. $P_2=P_3\ne P_1$

Answer 1

The correct option is A $P_1=P_2=P_3$

The pressure of different point on the same level is equal if there is no acceleration.

$P_1=P_2=P_3$

The correct option is A.