Question

A wooden slab, starting from rest, slides down an inclined plane of length 10m with an acceleration of 5m/s^2. What would be it's speed at the bottom of inclined plane?

Answer 1

Its acceleration is 5m/s²

So a=5m/s²

We need to find the final velocity i.e v

Using the equations of motion

v²-u²=2as

v²-0²=2*5*10

v²=100

v=√100

So v is 10

The final velocity of the Wooden slab is 10m/s