A work force of 50 men with a contractor can finish a piece of work in 5 months.
In how many months the same work can be completed by 125 men.
Let in x months, the work will be completed by 125 men
Men50125Period (in months)5x
More men, less period
∴ By inverse variation
50:125=x:5⇒50125=x5⇒50×5=125×x⇒x=50×5125=2
∴ Period = 2months.