CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A worker drags a crate across a factory floor by pulling on a rope tied to the crate.The worker exerts a force of magnitude F " 450 N on the rope,which is inclined at an upward angle u " 383 to the horizontal, and the floor exerts a horizontal force of magnitude f " 125 N that opposes the motion. Calculate the magnitude of the acceleration of the crate if (a) its mass is 310 kg and (b) its weight is 310 N.

Open in App
Solution

Although the full specification of Fnet=ma in this situation involves both x and y axes, only the x-application is needed to find what this particular problem asks for. We note that ay=0 so that there is no ambiguity denoting ax simply as a. We choose +x to the right and +y up. The free-body diagram (not to scale) is shown below.

The x component of the rope’s tension (acting on the crate) is

Fx=Fcosθ=(450N)cos38o=355N,

and the resistive force (pointing in the –x direction) has magnitude f=125N.

(a) Newton’s second law leads to

Fxf=maa=Fcosθfm=355N125N310kg=0.74m/s2.

(b) In this case, we use Eq. 5-12 to find the mass: m=W/g=31.6kg. Now, Newton’s second law leads to

Fxf=maa=Fxfm=355N125N31.6kg=7.3m/s2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
What's with All the Tension in the Room?
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon