A works twice as fast as B. If B can complete a work in 24 days independently, the number of days in which A and B can together finish the work is?

12 days

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9 days

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8 days

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6 days

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None of these

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Solution

The correct option is C 8 days

(The no. of days is indirectly proportional to the efficiency)
Now, given that,
$2 x = 24$
$x = 12 d a y s$

The number of days in which A and B can together finish the work
$= \frac{2 x \times x}{2 x + x}$
$= \frac{2 x}{3}$
$= 8 d a y s$

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Similar questions

A works twice as fast as B. If B can complete a work in 24 days independently, the number of days in which A and B can together finish the work is?

Q. A works twice as that as B. If B can complete a work in 12 days independently, then the number of days in which A and B can together finish the work is

A works twice as fast as B. If both of them can together finish a piece of work in 12 days, then B alone can do it in

(a) 24 days

(b) 27 days

(d) 48 days

Q. Tick (✓) the correct answer:
A works twice as fast as B. If both of them can together finish a piece of work in 12 days, then B alone can do it in
(a) 24 days
(b) 27 days
(c) 36 days
(d) 48 days

A takes twice as much time as B or thrice as much time as C to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in how many days?

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A works twice as fast as B. If B can complete a work in 24 days independently, the number of days in which A and B can together finish the work is?

The correct option is C 8 days (The no. of days is indirectly proportional to the efficiency) Now, given that, 2x=24 x=12 days The number of days in which A and B can together finish the work =2x×x2x+x =2x3 =8 days

The correct option is C 8 days

(The no. of days is indirectly proportional to the efficiency)
Now, given that,
$2 x = 24$
$x = 12 d a y s$

The number of days in which A and B can together finish the work
$= \frac{2 x \times x}{2 x + x}$
$= \frac{2 x}{3}$
$= 8 d a y s$