Question

a. Write additive inverse of $\frac{2}{8}and\frac{-6}{-5}$
b. Write multiplicative inverse of $-13and\frac{-13}{19}$

Answer 1

$\begin{array}{c}a.\frac{2}{8}\to \frac{-2}{8}\\ \frac{-6}{5}=\frac{6}{5}\to \frac{-6}{5}\\ b.-13\to \frac{1}{-13}\\ \frac{-13}{19}\to \frac{-19}{13}\end{array}$