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Question

(a) Write the algebraic form of the arithmetic sequence 1,4,7,10,..
(b) Is 100 a term of this sequence? Why?
(c) Prove that the square of any term of this sequence is also a term of it.

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Solution

Sequence is 1,4,7,10,.....
(a) a=1,d=41=3
tn=a+(n1)d
tn=1+(n1)d
tn=1+3n3
tn=3n2 which is algebraic form of the given arithmetic sequence.
(b) tn=3n2
tn=3n2
3n=102
n=34
100 is the 34th term of the sequence.
(c) We know, tn=3n2
Square of the term of this sequence
=(3n2)2
=9n212n+4
=9n212n+128
=3[3n2)22]2
Let k=[(3n2)22]
Square of the term of this sequence =3k2
Since square of the sequence is of the form =3k2, therefore square of any term of the sequence is a term of this sequence.

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