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Question

a) Write the electronic configuration of Cu in s p d f

b) Which of the following orbitals has the lowest energy
4d, 4f, 5s, 5p

c) What is the wavelength of light emitted when the electrons in a hydrogen atom undergo the transition from an energy level n=4 to an energy level n=2?

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Solution

(a) Electronic configuration of Cu=1s22s22p63s23p63d104s1

(b)

4d n+1=4+2=6
4f n+1=4+3=7
5s n+1=5+0=5
5p n+1=5+1=6

So, 5s has the lowest energy.

(c)

1λ=RH(1h211h22)

1λ=RH(122142)

1λ=RH(14116)

λ=163RH

=163×91.6 Since, ( 1RH=91.6nm )

=488.5nm

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