(a) Write the name and electronic configuration of the third element from the top in group 15.
(b) Draw the structure of ammonia molecule.
(c) Why does $N H_{3}$ act as a Lewis base?
(d) Give equations for the reactions of dilute and concentrated $H N O_{3}$ and $Z n$ .

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Solution

(a) The third element from the top in group 15 is arsenic. Its electronic configuration is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{2} 4 p^{3}$
(b) The structure of ammonia molecule is as shown.
(c) $N H_{3}$ acts as a Lewis base as it has lone pair of electrons on N atom that can be easily donated to suitable lewis acid.
(d) The equations for the reactions of dilute and concentrated $H N O_{3}$ and Zn are as shown.
$4 Z n + 10 H N O_{3} (d i l) \to 4 Z n (N O_{3})_{2} + N H_{4} N O_{3} + 3 H_{2} O$
$Z n + 4 H N O_{3} (c o n c) \to Z n (N O_{3})_{2} + 2 N O_{2} + 2 H_{2} O$

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Question 42
An element is placed in 2nd Group and 3rd Period of the Periodic Table, burns in presence of oxygen to form a basic oxide.

(a) Identify the element.

(b) Write the electronic configuration.

(d) Write a balanced equation when this oxide is dissolved in water.

(e) Draw the electron dot structure for the formation of this oxide.

{C u}^{2 +}

{N H}_{3}

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