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Question

A={x:xR, x2=16 and 2x=6} can be represented in the roster form as _________ .


A

A={14,3,4}

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B

A={3}

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C

A={4}

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D

A={}

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Solution

The correct option is D

A={}


Given A={x:xR, x2=16 and 2x=6}

A is the set of common solutions of equations x2=16 and 2x=6
As x2=16x=±4
ans 2x=6x=3

There is no value of x which satisfies both the given equations.
The set A is an empty set or a null set.

Thus, A={}.


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