A={x:x∈R, x2=16 and 2x=6} can be represented in the roster form as _________ .
A = {}
A = { 14, 3, 4 }
A = { 3 }
A = { 4 }
x2=16⇒x=±4 2x=6⇒x=3
There is no value of x which satisfies both the given equations. The set A is an empty set or a null set.
Thus, A = {}.
The set A={x:xϵR,x2=16 and 2x=6} equals