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Distinguishing Test of Terminal and Non Terminal Alkynes

A Lindlar's C...

Question

$A L i n d l a r^{'} s \leftarrow ---- - Catalyst R - C \equiv C - R Birch reduction ⟶ B$
Where, A and B are geometrical isomers $(R - C H = C H - R)$ .
Choose the correct option from the following:

A is trans, B is cis

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A and B both are cis

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A and B both are trans

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A is cis, B is trans

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Solution

The correct option is D A is cis, B is trans
Birch reduction gives trans product and lindlar's catalyst gives cis. Hence correct option is (a).
Birch Reduction takes place in presence of $N a / l i q . N H_{3}$
Lindlar's catalyst is $H_{2}, P d / C$

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Similar questions

$B L i n d r a l / H_{2} \leftarrow ------ - R - C \equiv C - R N a / N H_{3} - ---- \to$ A and B are geometrical isomers (R - CH = CH - R):

A L i n d l a r^{'} s \leftarrow ---- - Catalyst R - C \equiv C - R Birch reduction ⟶ B

(R - C H = C H - R)

$B L i n d r a l / H_{2} \leftarrow ------ - R - C \equiv C - R N a / N H_{3} - ---- \to$ A and B are geometrical isomers (R - CH = CH - R):

C H_{2} - C H = C H_{3}

C H_{3} - C H = C H - C H_{3}

C H_{3} - C H = C = C H - C H_{3}

C H_{3} - C H = C = C = C H - C H_{3}

[M (A B) b_{2} c d]

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