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Question

A Young's double slit apparatus has slits separated by 0.28 mm and a screen 48 cm away from the slits. The whole apparatus is immersed in water and the slits are illuminated by the red light (λ=700 nm in vacuum). Find the fringe-width of the pattern formed on the screen.

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Solution

Given that, d=0.28 mm=0.28×103m,D=48 cm=0.48 m,λa=700 nm in vacum
Let λw= wavelength of red light in water
Since, the fringe width of the pattern is given by.
β=λwDd=525×109×0.480.28×103=9×104m=0.90 mm

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