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Question

A Young's modulus of the material of a wire is 2×1010Nm2. If the elongation strain is 1 the energy stored in the wire per unit volume in Jm3 is

A
106Jm3
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B
108Jm3
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C
2×106Jm3
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D
2×108Jm3
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Solution

The correct option is A 106Jm3
Given Strain =ΔLL=1100
young's modulus of wire =2×1010 N/m2
we know; Energy stored per unit volume =12× stress × strain y= stress strain
E=12×( strain )2×y
=12×(1100)2×2×1010E=106 J

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