A Zener diode offers infinite resistance as long as the reverse voltage across it is less than the break-down value.
As soon as the reverse bias voltage cross the break-down level, the residue voltage remains in the circuit, with the diode offering zero resistance to it.
Hence, here the voltage remaining across the Zener
=10−5.6=4.4 V
Therefore, the current in the circuit is
IZ=4.4100=4.4×10−2 A=44 mA
Hence, 44 is the correct answer.