A zener diode having breakdown voltage equal to 15V, is in a voltage regulator circuit as shown in figure. The current through the diode is
A
5mA
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B
10mA
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C
15mA
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D
20mA
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Solution
The correct option is A5mA Here, zener diode is connected parallel to the 1kΩ so the voltage across CD will be equal. Let current i be flowing between point A and B
now calculating current as i=20−15250=20mA Now i2=15−01000=15mA By using Junction rule at point B: i=i1+i2i1=i−i2i1=20−15=5mA