A zener diode having breakdown voltage equal to 15V, is in a voltage regulator circuit as shown in figure. The current through the diode is
A
5mA
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
10mA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
15mA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
20mA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A5mA Here, zener diode is connected parallel to the 1kΩ so the voltage across CD will be equal.
Let current i be flowing between point A and B
now calculating current as i=20−15250=20mA
Now i2=15−01000=15mA
By using Junction rule at point B: i=i1+i2i1=i−i2i1=20−15=5mA