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Transistor: Working

A zener diode...

Question

A zener diode is specified as having a breakdown voltage of 9.1 V with a maximum power dissipation of 364 mW. what is the maximum current the diode can handle?

A

50mA

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B

45mA

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C

40mA

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D

60mA

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Solution

The correct option is B 40mA
Given : Breakdown voltage, $V_{m a x} = 9.1 V$
Maximum power $P_{m a x} = 364 m W$

For zener diode, $P_{m a x} = I_{m a x} V_{m a x}$

$I_{m a x} = \frac{P_{m a x}}{V_{m a x}} = \frac{364}{9.1} = 40 m A$

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