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Faraday's Second Law

A Zinc electr...

Question

A Zinc electrode is placed in a $0.1 M$ solution at $25^{o} C$ . Assuming that salt is dissociated to $20$ % at this dilution, calculate the electrode potential.
Given : $E_{Z n^{2 +} / Z n} = - 0.76 V$

1.23

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0.81

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Solution

The correct option is D - $0.81$ V
$[Z n^{2 +}] = 0.1 M \times \frac{20}{100} = 0.02$
$E_{e l} = E_{e l}^{o} - \frac{0.0592}{n} l o g \frac{1}{[Z n^{2 +}]}$
$E_{e l} = - 0.76 - \frac{0.0592}{2} l o g \frac{1}{0.02}$
$E_{e l} = - 0.76 - 0.05$
$E_{e l} = - 0.81$ V

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