A zinc plate was kept in a glass container having $C u S O_{4}$ solution. On examining it was found that the blue colour of the solution is getting lighter. After a few days, when the zinc plate was taken out of the solution, a number of small holes were noticed in it. State the reason and give chemical equation of the reaction involved.

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Solution

Answer :

Zinc is more reactive than copper and hence zinc displaces copper from copper sulphate solution to form zinc sulphate solution, which is of green colour, and copper. It is due to formation of the green zinc sulphate solution that the blue colour of copper sulphate gets lighter and lighter.
Zinc from the rod reacts with the solution to form zinc sulphate solution. So the plate has a number of small holes in it.

$Z n$ (s) + $C u S O_{4}$ (aq) $⟶$ $Z n S O_{4}$ (aq) + $C u$ (s)

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