A 12- -A- 0-88B- 0-75C- 0-98D- 1-25

The correct option is A 0.88D’s 1 unit = E’s A12 unit. From the table D’s 1.25 unit = E.s 1.1 unit from these D.s 1 unit = 1/1.25 x1.1 = 0.88 unit of E. ...

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Standard VII

Mathematics

Conversion of Units of Measurement

A 12= ?A. 0.8...

Question

A₁₂= ?

0.75

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0.98

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1.25

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0.88

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Solution

The correct option is D 0.88
D’s 1 unit = E’s A₁₂ unit. From the table D’s 1.25 unit = E.s 1.1 unit from these D.s 1 unit = 1/1.25 x1.1 = 0.88 unit of E.

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Similar questions

A_{12}

= ?

Q. If

\sqrt{2} = 1.41

, then

\frac{1}{\sqrt{2}}

=?
(a) 0.075
(b) 0.75
(c) 0.705
(d) 7.05

Q. If

\sqrt{2} = 1.41 then \frac{1}{\sqrt{2}} = ?

(a) 0.075
(b) 0.75
(c) 0.705
(d) 7.05

Q. If

⎡ ⎢ ⎣ \begin{matrix} cos θ - sin θ 0 \end{matrix} \begin{matrix} sin θ cos θ 0 \end{matrix} \begin{matrix} 001 \end{matrix} ⎤ ⎥ ⎦

then the value of

a_{11} A_{11} + a_{12} A_{12} + a_{13} A_{13} =

where

A_{11}, A_{12} A_{13}

are cofactors of

a_{11}, a_{12}, a_{13}

respectively

A particle is subjected to two simple harmonic motions given as $x_{1} = A_{1} s i n ω t$ and $x_{2} = A_{2} s i n (ω t + \frac{π}{3})$

Find A. the displacement at t = 0

B. the maximum speed of the particle and

C. the maximum acceleration of the particle

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A12= ?

The correct option is D 0.88D’s 1 unit = E’s A12 unit. From the table D’s 1.25 unit = E.s 1.1 unit from these D.s 1 unit = 1/1.25 x1.1 = 0.88 unit of E.

A₁₂= ?

The correct option is D 0.88
D’s 1 unit = E’s A₁₂ unit. From the table D’s 1.25 unit = E.s 1.1 unit from these D.s 1 unit = 1/1.25 x1.1 = 0.88 unit of E.